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βi=1nc\sum_{i=1}^n cβi=1nβc
cn
c + c + c + ... + c
βi=1ni\sum_{i=1}^n iβi=1nβi
n(n+1)2\frac {n(n+1)} 22n(n+1)β
1 + 2 + 3 + ... + n
βi=1ni2\sum_{i=1}^n i^2βi=1nβi2
n(n+1)(2n+1)6\frac {n(n+1)(2n+1)} 66n(n+1)(2n+1)β
1 + 4 + 9 + ... + n^2
βi=0nri\sum_{i=0}^n {r^i}βi=0nβri
r(n+1)β1rβ1\frac {r^{(n+1)} - 1} {r-1}rβ1r(n+1)β1β
r1+r2+r3+rnr^1 + r^2 + r^3 + r^nr1+r2+r3+rn
Last updated 1 year ago