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∑i=1nc\sum_{i=1}^n c∑i=1nc
cn
c + c + c + ... + c
∑i=1ni\sum_{i=1}^n i∑i=1ni
n(n+1)2\frac {n(n+1)} 22n(n+1)
1 + 2 + 3 + ... + n
∑i=1ni2\sum_{i=1}^n i^2∑i=1ni2
n(n+1)(2n+1)6\frac {n(n+1)(2n+1)} 66n(n+1)(2n+1)
1 + 4 + 9 + ... + n^2
∑i=0nri\sum_{i=0}^n {r^i}∑i=0nri
r(n+1)−1r−1\frac {r^{(n+1)} - 1} {r-1}r−1r(n+1)−1
r1+r2+r3+rnr^1 + r^2 + r^3 + r^nr1+r2+r3+rn
Last updated 2 years ago